Hello, everybody!

Can anybody help me with understanding of implementation of this stdp-like rule at brian.

```
w=Aplus* th[((-deltat-aplus)/tauplus) +1] +bplus* deltat>=0
w=Aminus* th[((deltat-aminus)/tauminus)+1] +bminus* deltat<0
```

Hello, everybody!

Can anybody help me with understanding of implementation of this stdp-like rule at brian.

```
w=Aplus* th[((-deltat-aplus)/tauplus) +1] +bplus* deltat>=0
w=Aminus* th[((deltat-aminus)/tauminus)+1] +bminus* deltat<0
```

Hi @serge25 Could you give some more information about where these equations come from? They are not in Brian syntax, and I am not quite clear what e.g. `th`

means.

Hi @mstimberg . This is not from somewhere. It is some kind of reflection about this dependence. Th - hyperbolic tangent.

Even more reason to give details ! I guess that `deltat`

is the time difference between the pre- and post-synaptic spike, but I’m having trouble following the rest: there are two different equations for `w`

, do you mean to apply one for `deltat <0`

and one for `deltat>=0`

? The equations are given as `w = ...`

, but I guess you rather mean something like `w += ...`

to update the weight?

All that said, the following should be helpful: if the pre- and post-synaptic neurons use refractoriness, then they automatically provide a `lastspike`

variable that you can use. If not, you can simply add `lastspike : second`

to their equations, and `lastspike = t`

to their reset statement. Then you can use something like this in `on_pre`

:

```
deltat = lastspike_post - t
```

and this in `on_post`

:

```
deltat = t - lastspike_pre
```

You then can update your weight as a function of `deltat`

, the difference between the pre and postsynaptic spike (i.e. negative when post spikes before pre). Note that if you want to add something under a certain condition, rather use an expression like `int(deltat>=0)`

instead of `deltat>=0`

to not confuse Brian’s/sympy’s equation parsing. Finally, the hyperbolic tangent function is available as `tanh`

.

@mstimberg , thank you very much for your answer.